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What statement is correct for $f(A, B)$ in the following circuit?

  1. $f(A, B)=\overline{\overline{A \cdot B} \cdot(A+B)}$ when Control $=1$
  2. $f(A, B)=A \cdot B$ when Control $=0$
  3. $f(A, B)=\overline{A}+\overline{B}$ when Control $=1$
  4. $f(A, B)=\overline{A} \cdot \overline{B}$ when Control $=0$
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Why A is not the correct answer , If control input is 1 Nand output  Ab’ and or gate is a+b and now we  again pass to nand gate (AB’ .(A+b))’
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when control input is 1 top NAND will give $\overline{A.B}$

OR will give 1 (or is 1 when atleast 1 is 1)

finally give $\overline{\overline{A.B}.1}=\overline{\overline{AB}}+0=AB$

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1 Answer

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NAND output is one if atleat one input is 0

OR output is 1 when atleast 1 input is 1

 

when control signal is 0

Top NAND will be 1 OR will be $OR(0,A,B)=OR(A,B)$ resulting in

$NAND(1,A+B)=\overline{A+B}=\overline{A}.\overline{B}$

 

when control input is 1 top NAND will give $\overline{A.B}$

OR will give 1 (or is 1 when atleast 1 is 1)

finally give $\overline{\overline{A.B}.1}=\overline{\overline{AB}}+0=AB$

 

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