Sir, I have a question in this answer, since we have odd number of keys per node, i.e. here there are 19 keys per node so when we add the 20th key to any node it divides the node in half (9 keys a left side, 1 key at upper level and, 10 keys at right side).
If we follow this and think of it as divide node has went on third level and the break is so in the 2nd level.
Then the 9 keys on left = 10 pointers on left node each having 9 keys = 90 keys in left side
and 10 keys on right side = 11 pointers, with 10 pointers having 9 keys and 1 pointer with 10 keys) =100
therfore answer should be 190.
can u please help me with what is wrong in this? and let me know abt a test case with Even order giving the answer in that manner?