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3 votes
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The product of all eigenvalues of the matrix $\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right]$ is

  1. $-1$
  2. $0$
  3. $1$
  4. $2$ 
in Linear Algebra edited by
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7 Answers

1 vote
1 vote

Product of eigen values is Determinant of the matrix.
Since, Columns are Linearly Dependent (C3 = 2*C2 - C1) we can say Determinant will be zero.

(B) is correct option.
 

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Product of eigen values is the determinant of the matrix.

Here the rows are linearly dependent as follows:

row3 = 2*row2 - row1

Thus, the determinant is zero.

Answer: option B
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All columns of the matrix are Linearly Dependant on each other, so the determinant is 0.

Hence the correct answer is B.
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B)0
Answer:

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