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Consider a disk with the following specifications: rotation speed of $6000$ RPM, average seek time of $5$ milliseconds, $500$ sectors/track, $512$-byte sectors. A file has content stored in $3000$ sectors located randomly on the disk. Assuming average rotational latency, the total time (in seconds, rounded off to $2$ decimal places) to read the entire file from the disk is ______________.

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Total Time(T) = No. of sectors * ( Avg time per sector for random access)

 T= 3000 * ( Avg Seek Time + Avg Rotational Latency + Transfer Time)         

T= 3000* ( 5ms + 10/2 ms + 1/50 ms)

T= 30.06sec
Answer:

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