If points [1, 1] and [-1, 1] are both part of cluster 3 in the k-means clustering algorithm, it implies that they are closer to each other than to the centroids of the other clusters.
Since the clustering is based on Euclidean distance, any point that is closer to points [1, 1] and [-1, 1] than to the centroids of the other clusters will also be part of cluster 3.
Let's examine the given options:
- [0, 0] has a distance of √2 from both [1, 1] and [-1, 1].
- [0, 2] has a distance of √5 from both [1, 1] and [-1, 1].
- [2, 0] has a distance of 2√2 from both [1, 1] and [-1, 1].
- [0, 1] has a distance of 1 from both [1, 1] and [-1, 1].
Among the options, only [0, 1] has the same distance from both [1, 1] and [-1, 1]. Therefore, [0, 1] is necessarily also part of cluster 3.
So, the correct answer is:
D. [0, 1]