Peterson Davie 3.38a

Question

Suppose an $IP$ packet is fragmented into $10$ fragments, each with a $1$% (independent) probability of loss. To a reasonable approximation, this means there is a $10$% chance of losing the whole packet due to loss of a fragment. What is the probability of net loss of the whole packet if the packet is transmitted twice,

(a) Assuming all fragments received must have been part of the same transmission?

Answer 1

a)The probability of loosing both the packet is=0.1(chances of loosing 1st packet)*0.1(chances of loosing 2nd packet)=0.01

Answer 2

if whole packet is send twice then if probability of first loss is 10% then second time probability is 9.9%