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ISRO2009-50

in Calculus edited by
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6 votes
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The value of $x$ at which $y$ is minimum for $y=x^2 -3x +1 $ is

  1. $-3/2$
  2. $3/2$
  3. $0$
  4. $-5/4$
in Calculus edited by
by
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1 Answer

7 votes
7 votes
Best answer

Ans B) 3/2

y=x2-3x+1

y'=2x-3

y''=2 // So, y has minimum value

the value at point (2x-3)=0

or, x=3/2

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