How many characters per sec $(7 \;\text{bits} + 1 \;\text{parity})$ can be transmitted over a $2400$ bps line if the transfer is synchronous $( 1$ start and $1$ stop bit)?
Ans A) 300
Total number of bits per character while transmitting is (7+1)=8 bits
No of character transmitted 2400/8=300 bps
Awesome tricky question!
For synchronous transfer, we don't need start and stop bits.
So, $\frac{2400}{7+1}=300$
Option A
For asynchronous transfer, we need start and stop bits in order to synchronise!
So, $\frac{2400}{7+1+1+1}=240$
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