Question

why the o/p of this programm is 12 ?

#include<stdio.h>
int main()
{
int x = 10;
int y = (x++, ++x);
printf("%d", y);
getchar();
return 0;
}

Comments

Try to run this code from different compiler... There will be difference in out put...

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@gabbar can you explain the reason ?

Answer 1

If y =(value 1, value 2) y will be assigned with value 2.

Here initially  x=10

In (x++, ++x), the expression x++ makes x=11, then ++x again increments x to 12.

this final value is assigned to y

That's why output is 12

Comments

@shiva as you said y will get the value 2 then why we are even considering the x++ increment in this assignment y = (x++, ++x);

if this is the case

y =(value 1, value 2)  y will be assigned with value 2. as you said

then this int y = (x++, ++x); should be simpily one time increment just to consider ++x.

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 int y = (x++, ++x);  compiler understands the line like this

• int y                         // y is an integer; allocate memory for it
• =                          // a value will be assigned
• (                      // one or more operations are bundled together
• x++                       // increment x by one x=11
• ,                             / / more operations are waiting, proceed!!
• ++x               //increment x by one x=12
• )            //operations are over, assign value of last  operation to y ; ie y=12
• ;           // line is completed.

Hope I could help you to understand

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@shiva yes it has explained lots of thing.