Test by Bikram | Digital Logic | Test 2 | Question: 30

Question

The excess $3$ code of decimal number $26$ is:

• A. $0100 1001$
• B. $01011001$
• C. $1000 1001$
• D. $01001101$

Comments

(26)_10 = (0010 0110)_bcd= (0101 1001)_xs3

Answer 1

Decimal number till 9 can be converted into excess 3 code

So 2 = 0010 and 6 = 0110

To convert into excess-3 add 3 to both digits

so Excess- 3 code = (0010 + 0011)  (0110 +0011)  = (0101) (1001) i.e. 59

Comments

So 2 = 0010 and 3 = 0011

its 2 = 0010 and 6 = 0110

(0010 + 0011) (0110 + 0100) = (0101 1001)

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@Prashant. Sir What if we wanted to convert 29 to excess 3? How'd we add 3 to the digit 9 and convert?

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@Sambhrant Maurya