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7
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1
GATE CSE 2006 | Question: 24
Given a set of elements $N = {1, 2, ..., n}$ and two arbitrary subsets $A⊆N$ and $B⊆N$, how many of the n! permutations $\pi$ from $N$ to $N$ satisfy $\min(\pi(A)) = \min(\pi(B))$, where $\min(S)$ is the smallest integer in the set of integers $S$, and $\pi$(S) is the set of ... $n! \frac{|A ∩ B|}{|A ∪ B|}$ $\dfrac{|A ∩ B|^2}{^n \mathrm{C}_{|A ∪ B|}}$
commented
in
Set Theory & Algebra
Sep 29, 2020
11.2k
views
gatecse-2006
set-theory&algebra
normal
set-theory
4
answers
2
GATE CSE 2016 Set 1 | Question: 36
What will be the output of the following pseudo-code when parameters are passed by reference and dynamic scoping is assumed? a = 3; void n(x) { x = x * a; print (x); } void m(y) { a = 1 ; a = y - a; n(a); print (a); } void main () { m(a); } $6,2$ $6,6$ $4,2$ $4,4$
commented
in
Compiler Design
Sep 4, 2020
24.0k
views
gatecse-2016-set1
parameter-passing
normal
7
answers
3
GATE IT 2005 | Question: 12
The numbers $1, 2, .\dots n$ are inserted in a binary search tree in some order. In the resulting tree, the right subtree of the root contains $p$ nodes. The first number to be inserted in the tree must be $p$ $p + 1$ $n - p$ $n - p + 1$
commented
in
DS
Jul 9, 2020
13.4k
views
gateit-2005
data-structures
normal
binary-search-tree
5
answers
4
GATE CSE 2004 | Question: 50
The relation scheme $\text{Student Performance (name, courseNo, rollNo, grade)}$ has the following functional dependencies: name, courseNo, $\rightarrow$ grade rollNo, courseNo $\rightarrow$ grade name $\rightarrow$ rollNo rollNo $\rightarrow$ name The highest normal form of this relation scheme is $\text{2NF}$ $\text{3NF}$ $\text{BCNF}$ $\text{4NF}$
commented
in
Databases
Jun 25, 2020
17.7k
views
gatecse-2004
databases
database-normalization
normal
4
answers
5
GATE IT 2005 | Question: 74
In a communication network, a packet of length $L$ bits takes link $L_1$ with a probability of $p_1$ or link $L_2$ with a probability of $p_2$. Link $L_1$ and $L_2$ have bit error probability of $b_1$ and $b_2$ respectively. The probability that the packet will be received without ... $[1 - (b_1 + b_2)^L]p_1p_2$ $(1 - b_1)^L (1 - b_2)^Lp_1p_2$ $1 - (b_1^Lp_1 + b_2^Lp_2)$
commented
in
Computer Networks
May 30, 2020
8.8k
views
gateit-2005
computer-networks
error-detection
probability
normal
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