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A demand paging system takes 250 time units to service a page fault and 450 time units to replace a dirty page. Memory access time is 10 time units. The probability of page faults is 0.3. In case of a page fault, the probability of page being dirty is 0.06. The average access time is ________ time units (Upto 1 decimal place)
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$0.3 ( 0.94*250 + 0.06 * 450) + 0.7 (10) = 85.6$
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@ashwin

by looking your answer i getted doubt thats why i posted it again now correct
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Yes i don't know how i got 88 1 month ago :p
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88.3 time units

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