The cube root of a natural number n is defined as the largest natural number m such that (m^3≤n) . The complexity of computing the cube root of n (n is represented by binary notation) is
Can any one explain it , let n=9 =1001
and let m is 2 ,3 ,4
when m=2 0010 * 0010 * 0010 <= 1001
when m=3, 0011 * 0011 * 0011 <=1001
when m =4 , 0100 * 0100 * 0100 <=1001
How it is log n ?? Explain Plz