Answer is Option C.
Here, A1.evenx is checking whether number of x's are even or odd in A1.
But A has 1 more x than A1. Because A = xA1y(Hence one x is appended). (A.n or A1.n => counting number of x's)
Hence option B = A.n = A1.n + 1
And by taking mod it checks whether they are even or odd.
Now Option A is ofcourse true because A has 1 more x than A1. Hence if A1 calculates x's as even definitely A has +1 (hence even changes to odd and viceversa)