MadeEasy Test Series 2017: Computer Networks - Communication

Question

Assume there are 100 nodes are connected to a 1000 meter length of the coaxial cable. Using some protocol, each node can transmit 50 frames/second, where the average frame length is 2500 bits. The transmission rate at each node is 108 bps. The efficiency of this protocol is ________. (Upto 1 decimal place)

I got .125 but given is 12.5%?Please check which is correct?

Comments

"here every node is transmitting 50frame/se means 50*2500=125000bits/second(throughput)   and channel bw is 10⁸bits/second

$\eta$ * BW=Throughput

$\eta$=125000/10⁸ =125*10-5*100 %=>0.125% 

---

why %age in the end?

---

η=125000/10⁸ =125*10^-5=>0.00125 or 0.125%