MadeEasy Test Series 2017: Computer Networks - Communication

Question

Assume there are 100 nodes are connected to a 1000 meter length of the coaxial cable. Using some protocol, each node can transmit 50 frames/second, where the average frame length is 2500 bits. The transmission rate at each node is 108 bps. The efficiency of this protocol is ________. (Upto 1 decimal place)

I got .125 but given is 12.5%?Please check which is correct?

Comments

each node bandwidth*no of nodes=125000*100=125*10^5

125*10^5/10^8= 125*10^-3*100=12.5%

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also getting 0.125 or 12.5%.

see "each node can transmit 50 frames/second" and we have 100 nodes...(i guess you didn't multiply 100)

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considering 100 nodes we get .125.But question does not aks %age.,So to get 12.5% ,we should multiply by 100 but it is not asked in questions.

After multiplying with 100(considering 100  nodes) then only we get .125.Please check

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yes...they should have mentioned they want the answer in "%age" form....that's ambiguous.

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So without that answer should be .125 ,right?

Because in gate questions they specific mention if %age is required

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efficiency is always represented in percentage.

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"here every node is transmitting 50frame/se means 50*2500=125000bits/second(throughput)   and channel bw is 10⁸bits/second

$\eta$ * BW=Throughput

$\eta$=125000/10⁸ =125*10-5*100 %=>0.125% 

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why %age in the end?

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η=125000/10⁸ =125*10^-5=>0.00125 or 0.125%