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Made Easy mock test 1 Q:16 (2017-18)
G.K.T
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Mathematical Logic
Jan 16, 2018
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Which of the following is true for the predicate logic P ?
~ $\forall z[P(z) \rightarrow ($~$Q(z)\rightarrow P(z)) ]$
a.) P is satisfiable
b.) P is Tautology
c.) P is Contradiction
d.) None of these
G.K.T
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Anu007
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Jan 16, 2018
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Now check...
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G.K.T
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Jan 16, 2018
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But I have propagated the negation all the way till end in the expression
I have negated Q an P as well
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gauravkc
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Jan 16, 2018
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The expression in square brackets is true. It's a tautology.
But how to evaluate ~ ∀z [tautology] in logic terms?
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