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In a 32 bit machin we divide the VA into 4 segments

10bit ---8 bit ---6 bit --8 bit . We use a 3 level page such that first 10 bit are used for the first level and so on .

then what is size of a page table for a process that has a address 0 ?

a 4096 bytes

b 4274 bytes

c 4608 bytes

d 2148 bytes
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We have 3 levels of page tables. And address 0 is for start address? Where is the question taken from?
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I think I got this link for describing a GATE 2009 question. All answers are nicely explained here. A must read.
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Will do now . Thank you :)
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@Arjun sir,

in above pdf in problem 2 in Q3 

  1. If the average process size is 8GB, would you use a one-level, two-level, or three-level page table? Why?

how they calculate 3 level page table like 8 8 7 13..

my question is deu to page offset is 2^13 and page table entry is 4 bytes

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