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First Order Logic: GATE2005-41 ( From gate Overflow volume 1)
rambo1987
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Mathematical Logic
Sep 29, 2018
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May 6, 2021
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Shiva Sagar Rao
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Can the answer to this be "∀x ∃y (teacher (x) ∧ student (y) ∧ likes (y,x))" ?
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rambo1987
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Shiva Sagar Rao
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Mk Utkarsh
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Sep 30, 2018
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Everyone is teacher in this logic
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logan1x
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Oct 4, 2018
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Is answer " some students like all teachers"?
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manisha11
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Oct 5, 2018
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All teachers are liked by students?
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arvin
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Oct 5, 2018
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all teachers are liked by some students*
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For every x, if x is a teacher, there exists y, if y is a student, then y likes teacher x.
saurav546
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Jan 17, 2021
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GO 2023 Topic Wise Free Test 2 | First Order Logic | Question: 1
In first-order logic, how would you express that "something likes something"? $\exists x \exists y \operatorname{Likes}(x, y)$ $\exists x \forall y \operatorname{Likes}(x, \mathrm{y})$ $\forall x \exists y \text{Likes}(x, y)$ $\forall x \forall y \operatorname{Likes}(x, \mathrm{y})$
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Propositional and First Order Logic GATE-CS-2006
In the question whether this statement is a tautology ((A ∨ B) → C)) ≡ ((A → C) ∨ (B → C)) , If I take first part ((A ∨ B) → C)) as P and second part ((A → C) ∨ (B → C)) as Q , do I need to prove P-->Q is true? or both P-->Q and Q-->P as true? I am confused about the ≡ symbol.
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