in Digital Logic
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The Cout function of a 3-bit adder is as follows:

AB + Cin (A ⊕ B) ----- i

It, being a majority function, can also be written as:

AB+BCin+CinA

which is equivalent to

AB + Cin (A+B) ------- ii

So, if we consider eqn i and ii, doesn't it show that (A ⊕ B) = (A+B). What am I missing here?

in Digital Logic
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Here is how all three equations are the same:

 

 

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