WEST BENGAL SET COMPUTER SCIENCE

Question

A CPU has 32 bit-memory address and eacch word has size of 1 byte.

Answer 1

Answer $B$
No. of sets$= \frac{CS}{4*BS} = \frac{256KB}{BS*4} = 2^{12} = 4096$
size of tag $=16$bits
Number of sets$ =4096$
Set associativity $=4$
Extra memory required to store the tag bits $=16×4096×4-bits=2^{18} bits=2^{15} bytes$