The following circuit compares two $2$-bit binary numbers, $X$ and $Y$ represented by $X_1X_0$ and $Y_1Y_0$ respectively. ($X_0$ and $Y_0$ represent Least Significant Bits)
Under what conditions $Z$ will be $1$?
The output equation will be $(X_1⊙Y_1).(X_0.\overline{Y}_0)+X_1.\overline{Y}_1$ Clearly, when $X=0$, ie, when $X_0$ and $X_1$ are both $0$, output can't be 1. So, Options B, C and D are incorrect, because in them, $X=0$ is valid.
Option A
The The rhe the conditions ZZ will be 1 is X>Y
THEREFORE:
OPTION A)
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