The smallest integer that can be represented by an $8$-bit number in $2$'s complement form is :
Range of $n-bit$ $2's$ complement numbers is : $-2^{n-1}$ to $2^{n-1}-1$ (Refer: Range of integers in 2's complement)
For $n=8$, the smallest number that can be represented is : $-2^{8-1}=-2^{7}=-128$
Option B is correct.
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