Even number

Question

How many 4 digit even number are possible with each digit  distinct ?

Answer 1

Number of Numbers ending with 0
= 9*8*7*1 = 504
(rightmost position 0 i.e. one choice, rest of the 3 places with 9*8*7 ways..)

Number of Number ending with 2,4,6,8
= 8*8*7*4 = 1792
(rightmost position one out of four(2,4,6,8) number, 1st position from left is one out of eight (Except 0 and rightmost bit number) number, rest of the two choices can be any number i.e. 8*7 choices..)

Total = 1792 + 504 = 2296

Comments

can you extend your solution , how get 8*8*7*4

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check again !!!
i think it is sufficient..

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thanks now i get it