in Probability retagged by
444 views
6 votes
6 votes

Let $x$ be a random variable possessing the probability density function
$$
f(x)= \begin{cases}c x & , x \in[0,10] \\ 0 & , \text { otherwise }\end{cases}
$$
where $c \in \mathbb{R}$. The probability that $x \in[1,2]$ is ______.

  1. $\dfrac{1}{100}$
     
  2. $\dfrac{3}{100}$
     
  3. $\dfrac{5}{100}$
     
  4. $\dfrac{7}{100}$
in Probability retagged by
444 views

1 comment

$ \large{\colorbox{yellow}{Detailed video solution of this question with direct time stamp}}$

All India Mock Test 4 - Solutions Part 1

0
0

1 Answer

6 votes
6 votes

\[
\int_{0}^{10} cx \,dx = c\left[\frac{x^2}{2}\right]_{0}^{10} = \frac{c}{2}(10^2 - 0^2) = \frac{c}{2} \times 100=1
\]

 $c = \frac{2}{100}$

\[
\int_{1}^{2} \frac{2}{100}x \,dx=\frac{2}{100}\left[\frac{x^2}{2}\right]_{1}^{2} = \left[\frac{x^2}{100}\right]_{1}^{2} = \frac{2^2}{100} - \frac{1^2}{100} = \frac{4 - 1}{100}=\frac{3}{100}
\]

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true