The given DFA accepts all & only binary strings containing Odd number of $1's.$
So, option A is correct regular expression.
Option B Counter-Example: Generates empty string.
Option C Counter-Example: Doesn't generate $10011.$
Option D Counter-Example: Doesn't generate $1.$
WHY Option A: Go to the final state by reading $0^*1$, then stay in the final state by making either loop $0$ or loop $10^*1$ in any order, any number of times. So, $0^*1(0 + 10^*1)^*$ is the correct regular expression.