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​​​​​​The $15$ parts of the given figure are to be painted such that no two adjacent parts with shared boundaries (excluding corners) have the same color. The minimum number of colors required is

  1. $4$
  2. $3$
  3. $5$
  4. $6$

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How answer is A, can anyone explain?

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try coloring the graph from the inner circle.
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4
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A. 4 

We can't color with using only 3 colors.

As given graph is planar so minimum no. of colors required to  is 4.

Well known four color theorem says "every planar graph is four-colorable".

https://en.wikipedia.org/wiki/Four_color_theorem

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