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If the maximum output voltage of a DAC is $V$ volts and if the resolution is $R$ bits then the weight of the most significant bit is ________

  1. $V/(2^R -1)$
  2. $(2^{R-1}).V/(2^R-1)$
  3. $(2^{R-1}).V$
  4. $V/(2^{R-1})$
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CAN ANY1 provide a solution???
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is this in gate syllabus?
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1 Answer

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Best answer

Answer is B).

For DAC (Digital to analog convertor) ===> Every input has a weight and the output voltage is the sum of the weights of 1's in the input.

If the maximum output voltage of a DAC is volts and if the resolution is bits, then,

Weight of least significant bit is ==> V/2- 1

Weight of second least significant bit is ==> 2V/2- 1

Weight of third least significant bit is ==> 4V/2- 1

Weight of fourth least significant bit is ==> 8V/2- 1 , and so on................

Weight of Most significant bit is ==> (2R - 1 ) V/2- 1

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I did not understand anything but your answer is right...
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It was tough for me to understand, so i read a little bit about DAC and ADC... :)
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