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Answers by Vikas123

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1

ME mock1
Consider a binary tree, where for every node P – Q ≤ 2, where P represents number of nodes in left sub tree for node S and Q represents the number of nodes in right sub tree for node S for h > 0. The minimum number of nodes present in such a binary tree of height h =4 will be 6 8 9 None of these

answered in DS Jan 19, 2019

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2

UPPCL AE 2018:70
Consider the following grammar $\text{G:}$ $\text{P} \rightarrow \text{Q + R} \mid \text{Q - R} \mid \text{Q} \mid \text{R}$ $\text{Q} \rightarrow q \mid r$ $\text{R} \rightarrow r \mid s$ where $\text{P, Q,}$ and $\text{R}$ ... grammar $\text{G}$ Neither $\text{S1}$ nor $\text{S2}$ Only $\text{S1}$ Only $\text{S2}$ Both $\text{S1}$ and $\text{S2}$

answered in Compiler Design Jan 13, 2019

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3

made easy cbt1
FIFO replacement policy ignores locality of reference. true/false

answered in Operating System Jan 13, 2019

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4

answered in Databases Jan 13, 2019

259 views

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5

mad easy cbt 1
Let A be ternary tree with each node having 0 or 3 children . Let T have 25 node .The number of leaf nodes in ternary tree are

answered in Programming in C Jan 13, 2019

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6

permutation and combination
1 2 10 16

answered in Mathematical Logic Jan 13, 2019

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7

TLB hit ration and memory lookup time
Consider a system where TLB lookup time is $25$ ns and memory access time is $200$ ns, respectively. Assuming a virtual address space of $2$ KB, page size of $32$ bytes, and a PTE size of $2$ bytes, what is the minimum TLB hit ratio that results in an average v2p (virtual to physical) translation latency of $185$ ns?

answered in Operating System Jan 13, 2019

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8

me test series
A computer system implements a 38 bit virtual address, page size of 16 KB, and 256 entries translation look aside buffer (TLB) organized into 32 sets each having 8 ways. If TLB tag does not store any process id. The minimum length of TLB tag in bits is____

answered in Operating System Jan 11, 2019

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9

Madeeasy[CN-Flow control]
Consider two computers A and B are connected through a network of 30 Mbps.Assume the distance between them is 3000km and the signal propagation speed is same as the speed of light and the packet size is 12 KB. What is minimum number of bits required for window to achieve 100% utilization during GBN and SR protocol ?

answered in Computer Networks Jan 10, 2019

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10

Made easy test series

answered in Computer Networks Jan 8, 2019

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11

DBMS transaction
Which of the following is used to get back all the transactions back after rollback? a)Rollback b)Commit c)undo d)Redo

answered in Databases Jan 8, 2019

609 views

1 vote

12

MadeEasy Test Series 2019: Computer Networls - Congestion Control
Please help, I am getting total number of transmission to get BACK TO 38 as 14 and NOT 15. after 14th, it would have became 38, so no need to consider 15th segment right?

answered in Computer Networks Jan 8, 2019

980 views

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13

MadeEasy Test Series 2018: Compiler Design - Intermediate Code
The following program uses six temporary variables p, q, r, s, t and u. The code is : Assuming that all operations take their operands from registers. The minimum number of registers needed to execute this program without spilling are ... three lines and the last line are dead code. So the answer should be 2. Please correct me if wrong.

answered in Compiler Design Dec 24, 2018

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14

booth's multiplication algorithm
is booth's multiplication algorithm included in gate syllabus?

answered in CO and Architecture Dec 18, 2018

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15

ME TESTSERIES
If flooding is used to send packets from A to E, then the total number of packets generated in the above network when hop count for A to E is 3 are ________. ANSWER IS 14 .....BUT THE DOUBT IS THAT IS THEIR ANY EFFECT OF SAYING HOP COUNT FOR A TO E BECZ HERE IN 14 WE COUNTED THE HOP OF LENGTH...

answered in Computer Networks Dec 2, 2018

2.3k views

1 vote

16

GATE CSE 2003 | Question: 78
A processor uses $2-level$ page tables for virtual to physical address translation. Page tables for both levels are stored in the main memory. Virtual and physical addresses are both $32$ bits wide. The memory is byte addressable. For virtual to physical address translation, the ... virtual address is approximately (to the nearest $0.5$ ns) $1.5$ ns $2$ ns $3$ ns $4$ ns

answered in Operating System Aug 6, 2018

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