Test Series

Question

Consider the circuit with initial state Q₀=0,Q₁=0 and Q₂=0.

Then which of the following sequence of output is correct?

a)4, 6, 3

b)  1, 3, 7

c)  3, 6, 4

d)  7, 3, 1

Comments

How can $D_0$ can output $Q_{2}$ ??

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 @Anjan Yes, may be there is misprint what will be output if we replace Q2 by Q0....and in third flipflop Q0 by Q2..?

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A) is correct but Correct Counting sequence is 0 - 4 - 6 - 3 - 1 - 0.....

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@ Shubhanshu Sir, can you give solution So that i can improve my mistake..?

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To solve these types of question you need to construct a table. In this case you need a table of 6 columns and column names are Q2, Q1, Q0, D2, D1, D0 and then write the input to each D flipflop over them, like D2 input is Q1 EX-NOR Q0, D1 input is Q2 and D0 input is Q1.

This is an easy way to solve sync counter question.

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ok thanx @ Shubhanshu Sir, can you add an your answere...pic of solution..?

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ans is (b)