ISRO2018-3

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ISRO2018-3

Arjun asked Apr 22, 2018 • edited Jan 2, 2020 by `JEET

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Arjun asked Apr 22, 2018

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ISRO2018-19

Given $\sqrt{224_{r}}$= $13$$_{r}$ the value of radix $r$ is$10$$8$$6$$5$

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ISRO2018-32

A computer uses ternary system instead of the traditional systen, An $n$ bit string in the binary system will occupy$3+n$ ternary digits$2n/3$ ternary digits$n$$\log_{2}3...

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ISRO2018-9

In the diagram above, the inverter (NOT gate) and the AND-gates labeled $1$ and $2$ have delays of $9, 10$ and $12$ nanoseconds (ns), respectively. Wire delays are neglig...

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ISRO2018-62

Any set of Boolean operation that is sufficient to represent all Boolean expression is said to be complete. Which of the following is not complete ?$\text{{AND, OR}}$$\te...

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Arjun asked Apr 22, 2018

@rajatmyname FInal answer key still says option A is the answer. — habedo007, Oct 27, 2019
Can't understand how option A is correct.

suppose I have to represent 0 to 17.

to represent 17, we can use 5 bits( 4 bits upto 15 & then 1 more bit required).

but according to option A, it gives 6 bits to represent 17. — mrinmoyh, Jan 9, 2020
@MRINMOY_HALDER, No, see its clearly written in question to take the floor and not ceil.

so floor(log2 17) + 1 = 4 + 1 = 5. — Tuhin Dutta, Jan 9, 2020
@Kushagra, if you take n=128. according to option A we need log(128)+1=> 7+1=8 — sonveer tomar 1, Apr 22, 2018
@Kushagra How would you store variable having 0 value? log 0 is infinity, but it requires 1 bit to store. — Akhilesh Singla, Apr 22, 2018
Akhilesh when I wrote the answer I forgot to consider 0 as a factor. So,if we choose 0 then option A is wrong option D will be correct. But otherwise option A is correct. — Kushagra Chatterjee, Apr 22, 2018
@kushagra if you take n = 16 then option B will give a result floor( log₂(15) ) + 1 which is 4 but you need 5 bits to represent 16. The same srgument can be given for all the numbers of the form 2^k. Option A is the correct answer as per me. — surajumang08, Apr 22, 2018
surajumang08, what if we take 0. than log(0) is negative infinity so all 3 option are not following that property — sonveer tomar 1, Apr 22, 2018
In the question it is given that the variable n is taking only integral values from 0 to n which means that it is taking integral values in the open interval (0,n) So, it cant take the value 0 or the value n. If n=16 it cant take that value. @suraj — Kushagra Chatterjee, Apr 22, 2018

Akhilesh Singla · Answer 1 · 2018-04-22T16:16:05+0000

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Raj Kumar 7 · Answer 2 · 2020-01-02T03:54:32+0000

Let n=8, (i.e variable take value from 0 to 8) (take worst case)

in binary: x = log8(base to 2) = 3

But for representing the 8, we need at least (x+1) bit,

similarly for n bit, [log n(base to 2) + 1] bit required.

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ISRO2018-3

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