@KUSHAGRA गुप्ता How did you took 51’s binary form and took it to 3’s power? can you explain why that works?
This is the same calculator btw. For this specific question we can get the answer.
3^51 mod 5
→ (3 mod 5)^51 mod 5
→ (-2)^51 mod 5
→ ( -2( -2 )^50) mod 5
→ (-2( 4 )^25) mod 5
→ (-2 ( 4 mod 5 )^25 ) mod 5
→ (-2 (-1)^25) mod 5
→ (-2*-1) mod 5
→ 2 mod 5
→ 2 ANSWER
(3)⁵¹ mod 5
3*(3)⁵⁰ mod 5
3*(3²)²⁵ mod 5
3*(9)²⁵ mod 5
3*(9 mod 5)²⁵ mod 5 [a mod n = a - kn mod n]
3*(-1)²⁵ mod 5
3*(-1) mod 5
-3 mod 5 = 2 [a mod n = a+n mod n]
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