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The minimum number of literal obtained on simplifying the expression ABC + A’C + AB’C + A’BC are _______

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Min terms =  $\sum_{}^{}(1,3,5,7)$

Minimized Expression = $C$

Number of literals = $1$
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ABC+A’C+AB’C+A’BC

=AC(B+B’)+A’C(1+B)

=AC+A’C

=C(A+A’)

=C

$\therefore$ Minimum number of Literal =1
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