ISI2020-MMA: 27

Question

Let $f : \mathbb{R}\rightarrow \mathbb{R}$ be a continuously differentiable function and $f(1) = 4$. Then the value of

$$\lim_{x\rightarrow 1}\int_{4}^{f(x)}\frac{2t}{x - 1}dt$$

is.

• A. $8f’(1)$

• B. $2f’(1)$

• C. $4f’(1)$

• D. $f’(1)$

Answer 1

Answer (A).

Simple integration and appling Leibnitz Rule.