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Question

(1101)x = (241)16

x = ?

Answer 1

ans should be 8

x*x*(x+1)=576

8*8*9=576

Answer 2

$(1101)_x=(241)_{16}$ can be written as:

$1*x^0+0*x^1+1*x^2+1*x^3=1*16^0+4*16^1+2*16^2$

$x^3+x^2+1=577$

$x^3+x^2=576$

$\because 8^3=512,$if we put $x=8$ we get: $8^3+8^2=576$

So the base/radix value is $x=8$

Comments

Check do this on also !!!!

Look up each hexadecimal digit to obtain the equivalent group of four binary digits. You can use the table to make these conversions.

(2)16 = (0010)2
(4)16 = (0100)2
(1)16 = (0001)2

Group each value and remove zeros at left (if necessary) to get the partial result in base 2:

0010 0100 0001 = 1001000001

So, (241)16 = (1001000001)2

Rearange all the digits in sets of three starting from the LSB (far right). Add zeros to the left of the last digit if there aren't enough digits to make a set of three.

001 001 000 001

Use the table below to convert each set of three into an octal digit. In this case,

001=1, 001=1, 000=0, 001=1.

So, 1101 is the octal equivalent of hexadecimal number 241 (Answer).