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A bag contains $10$ red balls and $15$ blue balls. Two balls are drawn randomly without replacement. Given that the first ball drawn is red, the probability (rounded off to $3$ decimal places) that both balls drawn are red is ___________.

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Given that the first ball drawn is red, what is the probability that both balls drawn are red.

Simply means what is the probability of drawing a red ball when the bad contains 9 red balls and 15 blue balls.

Answer = $\frac{9}{9+15} = 0.375$
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Answer: 0.375

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Ans is 0.375

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"Given that first ball is red". So we just need to find P(R2|R1)
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@minip Have a recheck. Ans is 0.375

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