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Consider a memory management system that uses a page size of $2 \mathrm{~KB}$. Assume that both the physical and virtual addresses start from $0$. Assume that the pages $0,1,2$, and $3$ are stored in the page frames $1,3,2$, and $0$, respectively. The physical address (in decimal format) corresponding to the virtual address $2500$ (in decimal format) is ___________.

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So the final answer will be 3* 2028 +452=6596

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Answer - 6596

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To convert  VA to PA replace Page number with Frame Number.

2KB ~ 11 bit Offset. 
(2500)10=(100111000100)2

VA = Page Number  + Offset

Page Number | Offset

100111000100

Replace Page number with 3 for Physical Address. ( Given in the Question )

(3)10=(11)2

Frame Number |  Offset

1100111000100

(1100111000100)2 = (6596)10

Correct :  (C)  6596

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