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circular arrangement

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For every girl there are 2 boys one at left and other at right. so for 6 girls, 12 boys can be chosen in 15P12 ways.Now every girl and 2 boys are considered as group remaining 3 boys(15-12 boys) are also consider as groups.so we have total 9 group in total and this can be arrange in circular in (9-1)!=8!ways. Number of permutation satisfy the conditions equals 15P12*8!
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The boys can arrange them in 14! ways

there are 8 sits between atleat every 2 boys

Girls can arrange 8C3 ways

6 girls can arrange 6! ways

So, total 14! ⨉  8C3 ⨉ 6! ways

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Shivank121 asked Mar 19, 2023
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Can any one solve this , 6B and 4G ,at least 2 girls should be together in circular arrangement
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srestha asked Jan 31, 2019
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