cil-2017

Question

Answer 1

Answer D

Let is consider a number as 123456

• In to get $1^{st}$ digit from right  $\frac{123456}{10^{0}} = 123456 % 10$ = 6$
• In to get $2^{nd}$ digit from right  $\frac{123456}{10^{1}} = 12345  % 10$ = 5$
• In to get $3^{rd}$ digit from right  $\frac{123456}{10^{2}} = 1234    % 10   = 4$
• In to get $4^{th}$ digit from right  $\frac{123456}{10^{3}} = 123      % 10   = 3$
• In to get $i^{th}$ digit from right  $\frac{123456}{10^{i-1}} = 123      % 10   = 3$

So, if the number is N, its $i^{th}$ digit from right would be $\left [ \frac{N}{10^{i-1}} \right ] mod 10$