MadeEasy Subject Test 2018: Digital Logic - Digital Counters

Question

 

Comments

MOD 5 counter --> 5

Decade counter --> 10

Johnson counter -->2n

2bit ripple counter --> 4

fout = fin/total_MOD

 1*       =1.6/(5*10*2n*4)

$1*10^{6} = \frac{1.6*10^{9}}{400n}$

$n=4$

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@Na462

it may helpful https://gateoverflow.in/237318/counter

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Was anything wrong with my approach @Shaik Masthan

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no brother... that's why i mentioned the name for whom my comment

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I got it @Shaik Masthan       brother : )

@Hemanth_13  brother what's wrong with my approach I also did the same only I assumed x to be number of states and later divided it by 2 :/

 

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@Na462 On solving x = 8

And number of states = 2* number of flip flops 

you got 8--> here 8 means MOD 8 counter.

Now the question is for johnson counter how many flip flops are needed for a MOD 8 counter , we need 4 ( as it is 2n counter)