GATE2014 AE: GA-6

Question

Find the odd one in the following group: $\text{ALRVX, EPVZB, ITZDF,OYEIK}$

• A. $\text{ALRVX}$
• B. $\text{EPVZB}$
• C. $\text{ITZDF}$
• D. $\text{OYEIK}$

Comments

options A) to C) has 1 vowel in each of them while D) has 3 vowels. So answer is D)

Answer 1

Answer is D

For all words except D, $i^{th}$ letter of word and $i^{th}$ letter of the previous word is differing by $3$ letters.

Comments

Can we also think in terms of number of vowels present do D is odd one.

Because D has more than 1 vowel present.

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Another approach

• $A\xrightarrow{+11}L$
• $E\xrightarrow{+11}P$
• $I\xrightarrow{+11}T$
• $O\xrightarrow{+10}Y$

Option $(D)$ not follows a pattern.

Answer 2

Option D,

Distance between first and second alphabet is 10,

Distance between second and third is 5,

Distance between third and fourth is 3,

Distance between fourth an fifth is 1.

This is true for A,B,C and not for D.

Comments

your answer and answer given by @sanju both are same and correct one

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Differences between alphabets

+11,+6,+4,+2

OR

1---3=+18

3---5=+6

2---4=+10

Answer 3

HERE OPTION D IS DIFFERENT ..

distance between first two alphabet is equal in first three and D different

So option D i guess

Comments

but D having 3 vowels as O,E,I

Answer 4

why cant we think like this ? 

Only A is sorted w.r.t alphabets 

So A is the answer ..

Comments

Sorted order is more obvious ryt? :P

If some one had challenged this question, do you think marks would have been given for A as well?

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If  you think in a cyclic way, even 2nd, 3rd and 4th options are sorted.

ABC...WXYZABC...WXYZ and so on.

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yes  and if we think like this elements are in cycle                                                                                                            

 $\underbrace{ALRVX}$  9 5 3 1

$\underbrace{ EPVZB}$  9 5 3 1

$\underbrace{ ITZDF}$ 10 5 3 1

$\underbrace{ OYEIK}$  9 5 3 1

so shouldn’t be the C ans here 9 is number of alphabet in b/w A & L , 5 is alphabet b/w L & R , 3 is alphabets b/w R&V, 1 is alphabet b/w V&X.