16 votes 16 votes The output $F$ of the below multiplexer circuit can be represented by $AB+B\bar{C}+\bar{C}A+\bar{B}\bar{C}$ $A\oplus B\oplus C$ $A \oplus B$ $\bar{A} \bar{B} C+ \bar{A} B \bar{C}+A \bar{B} \bar{C}$ Digital Logic gate1987 digital-logic combinational-circuit multiplexer circuit-output + – makhdoom ghaya asked Nov 8, 2016 • recategorized Apr 22, 2021 by Lakshman Bhaiya makhdoom ghaya 4.5k views answer comment Share Follow See 1 comment See all 1 1 comment reply krish__ commented Dec 8, 2017 reply Follow Share An easy would be to convert the expression obtained to 0s and 1s. And then, you can notice the fact that there are all possible combinations of odd $\#1$s in each of the terms. Thus it would be the XOR of the inputs. 3 votes 3 votes Please log in or register to add a comment.
Best answer 21 votes 21 votes Answer is B) $A'B'C+AB'C'+A'BC'+ABC$ $=(A+B')(A'+B)C+A'BC'+AB'C'$ $=$$A\oplus B\oplus C$ srestha answered Nov 8, 2016 • edited Jun 26, 2018 by Milicevic3306 srestha comment Share Follow See all 12 Comments See all 12 12 Comments reply h0tsh0t commented Oct 8, 2017 reply Follow Share Hey, can you explain your answer, please? Shouldn't it be A'B'C + A'BC' + AB'C' + ABC? 0 votes 0 votes srestha commented Oct 8, 2017 reply Follow Share yes, that is 0 votes 0 votes Manu Thakur commented Dec 14, 2017 reply Follow Share yes, it's A⊕B⊕C, ex-or is an odd function, it means number of boolean variables in un-prime form will be odd. 0 votes 0 votes thehobo03 commented Dec 20, 2017 reply Follow Share Can you explain what you mean by un-prime form here? 0 votes 0 votes Manu Thakur commented Dec 20, 2017 reply Follow Share Thehobo03 A variable has two forms p(non-prime) p'(prime (or) complemented). in exor function there will always be odd number of non-prime variables in each minterm, 1 votes 1 votes air1ankit commented Dec 31, 2017 i edited by air1ankit Nov 16, 2019 reply Follow Share can you please explain how you got =(A+B')(A'+B)C+A'BC'+AB'C' by using A'B'C+AB'C'+A'BC'+ABC I am unable to understand this part can uh please explain @srestha 0 votes 0 votes shraddha priya commented Jan 16, 2018 reply Follow Share @srestha how to know if A is lsb or B is lsb for the select lines? 0 votes 0 votes Anu007 commented Jan 16, 2018 reply Follow Share It is like that if not given than you have to take MSB RHS side i.e. B here and LSB LHS i.e. A. 0 votes 0 votes srestha commented Jan 17, 2018 reply Follow Share yes, just general assumption 1 votes 1 votes srestha commented Nov 16, 2019 reply Follow Share @air1ankit it is simple $A'B'C+ABC=\left ( A\odot B \right )C$ Now $\left ( A\odot B \right )=\left ( A '+B\right )\left ( A+B' \right )$ 2 votes 2 votes Abhineet Singh commented Nov 10, 2020 reply Follow Share how have you assumed msb and lsb? 0 votes 0 votes raja11sep commented Sep 13, 2022 reply Follow Share @Abhineet Singh If nothing mentioned then by default rightmost is LSB and leftmost is MSB. 0 votes 0 votes Please log in or register to add a comment.
5 votes 5 votes Option B Put c=1 Ram Swaroop answered Jan 6, 2020 Ram Swaroop comment Share Follow See 1 comment See all 1 1 comment reply shashankrustagi commented Dec 18, 2020 reply Follow Share cool thanks 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes (B) You wont find any explanation like this shashankrustagi answered Dec 18, 2020 shashankrustagi comment Share Follow See all 0 reply Please log in or register to add a comment.