Pipeline q 18 CA

Question

A nonpipeline system takes 50 ns to process a task. The same task can be processed in a six segment pipeline with a clock cycle of 10 ns.  determine the speed up ratio of the pipeline for 100 tasks.

  a.  3.76     b. 4.76     c. 5.76     d. 2.76

Answer 1

S= nt_n/(n+k-1)t_p = 100*50/(100+6-1)*10 = 4.76
Option B

Comments

S= ntn/(n+k-1)tp = 100*50/(100+6-1)*10 = 4.76

why n+k-1 ?